![]() 1 2 A = (6)(5) Substitute 6 for d1 and 5 for d2. Quick Check 10-2ġ 2 A = d1d2Use the formula for the area of a kite. ![]() Areas of Trapezoids, Rhombuses, and Kites Lesson 10-2 Additional Examples A = 162 Simplify. 1 2 A = h(b1 + b2) Use the trapezoid area formula. You may remember that 5, 12, 13 is a Pythagorean triple. (continued) By the Pythagorean Theorem, BX2 + XC2 = BC2, so BX2 = 132 – 52 = 144. Areas of Trapezoids, Rhombuses, and Kites Lesson 10-2 Additional Examples Finding the Area Using a Right Triangle Because opposite sides of rectangle ABXD are congruent, DX = 11 ft and XC = 16 ft – 11 ft = 5 ft. Draw an altitude from vertex B to DC that divides trapezoid ABCD into a rectangle and a right triangle. The area of the car window is 504 in.2 Quick Check 10-2įind the area of trapezoid ABCD. Areas of Trapezoids, Rhombuses, and Kites Lesson 10-2 Additional Examples Real-World Connection A = 504 Simplify. 1 2 A = h(b1 + b2) Area of a trapezoid 1 2 A = (18)(20 + 36) Substitute 18 for h, 20 for b1, and 36 for b2. 10-2Īreas of Trapezoids, Rhombuses, and Kites Lesson 10-2 Notes 10-2Ī car window is shaped like the trapezoid shown. Areas of Parallelograms and Triangles Lesson 10-1 Lesson Quiz 150 ft2 15 m2 24 square units 187 in.2 6 cm 10-2Īreas of Trapezoids, Rhombuses, and Kites Lesson 10-2 Notes The height of a trapezoid is the perpendicular distance hbetween the bases. Find the total area of the shaded regions. A rectangular flag is divided into four regions by its diagonals. Find the height corresponding to the 6-cm base. The height corresponding to the 8-cm base is 4.5 cm. So, add the three areas: 3 + 4.5 + 6 = 13.5 units2. By Theorem 1–10, the area of a region is the sum of the area of the nonoverlapping parts. The area A of the rectangle is bh = (2)(3) = 6. The area A of the triangle on the right is bh = (3)(3) = 4.5. The area A of the triangle on the left is bh = (2)(3) = 3. This forms two triangles and a rectangle between them. Draw two segments, one from A perpendicular to CD and the other from B perpendicular to CD. So, add the three areas: 1 + 2 + 4 = 7 units2. The area A of the rectangle is bh = (2)(2) = 4. The area A of the triangle on the right is bh = (2)(2) = 2. The area A of the triangle on the left is bh = (1)(2) = 1. Draw two segments, one from M perpendicular to CB and the other from K perpendicular to CB. 1 2 1 2 1 2 Areas of Trapezoids, Rhombuses, and Kites Lesson 10-2 Check Skills You’ll Need Solutions 10-2Īreas of Trapezoids, Rhombuses, and Kites Lesson 10-2 Check Skills You’ll Need Solutions (continued) 4. By Theorem 1-10, the area of a region is the sum of the area of the nonoverlapping parts. The area A of the rectangle is bh = (4)(2) = 8. The area A of the triangle is bh = (1)(2) = 1. ![]() Draw a segment from S perpendicular to UT. Check Skills You’ll Need 10-2ġ.A = bh 2.A = bh 3. Find the area of each trapezoid by using the formulas for area of a rectangle and area of a triangle. Areas of Trapezoids, Rhombuses, and Kites Lesson 10-2 Check Skills You’ll Need (For help, go to Lesson 10-1.) Write the formula for the area of each type of figure.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |